wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A hydrocarbon A(C4H8) on reaction withHCl gives a compound B(C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C(C4H11N). On reacting with NaNO2 and HCl (low temperature) followed by treatment with water, compound C yields optically active alcohol(s). Ozonolysis of A(1 mole) gives 2 moles of acetaldehyde.
The compound C is:

A
Butan-2-amine
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
N, N-dimethylethanamine
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Diethylamine
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Butylamine
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Butan-2-amine
Ozonolysis is the clue here. On ozonolysis, A gives 2 moles of ethanal, so A is CH3CH=CHCH3.
The reactions are as follows:
CH3CH=CHCH3(A)HClCH3CH2Cl|CHCH3(B)

NH3−−1 moleCH3CH2NH2|CHCH3(C)HNO2−−−−−−−−(NaNO2+HCl)CH3CH2N2Cl|CHCH3

H2OCH3CH2OH|CHCH3(D)

(D) is optically active due to presence of chiral centre.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Preparation of Amines
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon