A hydrocarbon A(C4H8) on reaction withHCl gives a compound B(C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C(C4H11N). On reacting with NaNO2 and HCl (low temperature) followed by treatment with water, compound C yields optically active alcohol(s). Ozonolysis of A(1 mole) gives 2 moles of acetaldehyde.
The compound C is: