You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Introduction to Alkanes

A hydrocarbon...

Question

A hydrocarbon $A$ $(C_{5} H_{10})$ on addition of $H B r$ in presence of a peroxide forms $(C_{5} H_{11} B r)$ $B$ which is found to be resolvable into enantiomers. $A$ on addition of $H B r$ in aqueous medium produces $C$ which is an isomer of $B$ but can't be resolved. $A$ on reductive ozonolysis produced $(C_{4} H_{8} O)$ $D$ as one product. $D$ on catalytic reduction with $N a B H_{4}$ produced E $(C_{4} H_{10} O)$ which is resolvable. $E$ on dehydration with concentrated sulphuric acid produced $F$ $(C_{4} H_{8})$ which on ozonolysis followed by work-up with $Z n - H_{2} O$ produced two molecules of ethanol. Identify $A$ to $F$ .

Open in App

Solution

2-Bromopentane and 1-Bromopentane (B and C).After ozonolysis of A it produced aldehyde D. On treatment of $N a B H_{4}$ on D it produced primary alcohol, which undergoes reaction with sulphuric acid to formed alkene.

Suggest Corrections

Similar questions

Q. An organic compound has molecular formula A

(C_{7} H_{10})

and known to decolourized

B r_{2}

-water solution.A on reduction with

H_{2} / P t

produces B

(C_{7} H_{14})

. B on monochlorination with

C l_{2} / h v

produces four isomeric monochloro derivatives

C_{7} H_{13} C l

. A on ozonolysis followed by work-up with Zn-dimethyl sulphide affords two and only two products, one being methanal and other C

(C_{6} H_{8} O_{3})

. C is oxidised with acidic solution of dochromate to yields D

(C_{6} H_{8} O_{5})

which is soluble in

N a H C O_{3}

. D is reduced with

N a B H_{4}

to yield E

(C_{6} H_{10} O_{3})

which may be resolved into enantiomers. Identify A to E.

Q. An organic acid

A (C_{5} H_{10} O_{2})

reacts with

B r_{2}

in presence of phosphorus to produce a resolvable compound B. B on dehydrobromination yields C. C does not show geometrical isomerism and on decarboxylation gives an alkene D. D on ozonolysis gives E and F. Compound E gives positive Schiff's test but F does not. Give structures of A to F.

Q. An organic compound

A (C_{5} H_{10} O_{2})

reacts with

B r_{2}

in presence of phosphorus to produce

B

which can be resolved into enantiomers.

B

on dehydrobromination yields

C (C_{5} H_{8} O_{2})

which does not show stereoisomerism.

C

on decarboxylation gives an alkene which on further ozonolysis gives

D

and

E

D

gives Schiff's test but

E

does not. The correct identity of these compounds are:

Q. An alkene A

(C_{10} H_{20})

on oxidative ozonolysis yields two molecules of

(C_{5} H_{10} O)

B. B on treatment with

L i A I H_{4}

yields C

(C_{5} H_{12} O)

which can't be resolved into enantiomers. Which of following is correct?

Q. A

3^{o}

optically active alcohol

C_{9} H_{18} O

(A)

on dehydration with

c o n c . H_{2} S O_{4}

produces

C_{9} H_{16}

(B)

which exists in two stereoisomeric forms. Reductive ozonolysis of

B

produces acetaldehyde and

C_{7} H_{12} O

(C)

C

on treatment with

L i A l H_{4}

produces

D (C_{7} H_{14} O)

D

on dehydration produced following product

Identify the correct answers.

Join BYJU'S Learning Program

2-Bromopentane and 1-Bromopentane (B and C).After ozonolysis of A it produced aldehyde D. On treatment of NaBH4 on D it produced primary alcohol, which undergoes reaction with sulphuric acid to formed alkene.

2-Bromopentane and 1-Bromopentane (B and C).After ozonolysis of A it produced aldehyde D. On treatment of $N a B H_{4}$ on D it produced primary alcohol, which undergoes reaction with sulphuric acid to formed alkene.