A hydrocarbon (A) was found to have vapour density 36. It forms only a single mono chloro substitution product. Suggest (A) :

2 methyl butane

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cyclopropane

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neopentane

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n-pentane

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Solution

The correct option is C neopentane
As given, vapour density $= 36$ ; molecular weight $= 2 \times 36 = 72$
As we know, general formula of an alkane is $C_{n} H_{2 n + 2}$
$12 n + 2 n + 2 = 72$
$\Rightarrow n = 5$
Therefore, alkane is C $_{5}$ H $_{12}$

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