A hydrocarbon contains 10-5 g of carbon per 1 g of H- One litre vapours of hydrocarbon with molar mass 92 at 127- C and 1 atm pressure weighs 2-8 g- Find molecular formula of hydrocarbon-A- C6 H6B- C9 H10C- C14 H16D- C7 H8

The correct option is D From the weights of Carbons and Hydrogen, C : H 10.5: 1 = 11.5g Molar mass⇒ M = 92g 11.5 g of compound has 1g of H. ∴ 92 g of compo ...

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Standard X

Chemistry

Relative Molecular Mass

A hydrocarbon...

Question

A hydrocarbon contains 10.5 g of carbon per 1 g of H. One litre vapours of hydrocarbon with molar mass 92 at $127^{\circ}$ C and 1 atm pressure weighs 2.8 g. Find molecular formula of hydrocarbon.

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Solution

The correct option is B

From the weights of Carbons and Hydrogen,

C : H

10.5: 1 = 11.5g

Molar mass $\Rightarrow M = 92 g$

11.5 g of compound has 1g of H.

$∴$ 92 g of compound has $\frac{92 \times 1}{11.5}$ = 8 g of H

8 g of H $\Rightarrow$ 8g - atom of H

Remaining 84g of C = $\Rightarrow$ $\frac{84}{12}$ = 7 g atom of C.

$∴$ Formula is $C_{7} H_{8}$

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A hydrocarbon contains 10.5 g of carbon per 1 g of H. One litre vapours of hydrocarbon with molar mass 92 at 127∘C and 1 atm pressure weighs 2.8 g. Find molecular formula of hydrocarbon.

The correct option is B From the weights of Carbons and Hydrogen, C : H 10.5: 1 = 11.5g Molar mass⇒M=92g 11.5 g of compound has 1g of H. ∴ 92 g of compound has 92×111.5 = 8 g of H 8 g of H ⇒ 8g - atom of H Remaining 84g of C = ⇒ 8412 = 7 g atom of C. ∴ Formula is C7H8

A hydrocarbon contains 10.5 g of carbon per 1 g of H. One litre vapours of hydrocarbon with molar mass 92 at $127^{\circ}$ C and 1 atm pressure weighs 2.8 g. Find molecular formula of hydrocarbon.