A hydrocarbon contains 75% of carbon. Then its molecular formula will be :

C H_{4}

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C_{2} H_{4}

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C_{2} H_{6}

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C_{2} H_{2}

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Solution

The correct option is B $C H_{4}$
C H
mass per 100g 75 25
no of moles $\frac{75}{12}$
$= 6.25$ $\frac{25}{1}$
=25
Divide by 6.25 1 4
MF is $C H_{4}$

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Similar questions

X, Y, Z

hydrocarbons molecular formula are

C H_{4}, C_{2} H_{4}, C_{2} H_{2}

. These three are passed through porcelain tube containing ammonical cuprous chloride. The out coming gases would be:

Q. Which out of following hydrocarbons undergo addition reactions?

C_{2} H_{6}, C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2}

and

C H_{4}

Q. Which of the following hydrocarbons undergo addiction reactions?

C_{2} H_{6}

C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2}

and

C H_{4}

(a) What is a homologous series? Explain with an example.
(b) State two characteristics of a homologous series.
(c) The molecular formula of an organic compound is C₁₈H₃₆. Name its homologous series.
(d) Select the hydrocarbons which belong to the same homologous series. Give the name of each series.
CH₄, C₂H₂, C₂H₄, C₂H₆, C₄H₁₀, C₃H₄, C₃H₆
(e) What is meant by 'heteroatom'? Give examples. Write the names and formulae of two organic compounds containing different heteroatoms.

Find the oxidation number of elements in each case :

C

C H_{4}, C_{2} H_{6}, C_{3} H_{8}, C_{2} H_{4}, C_{2} H_{2}, H_{2} C_{2} O_{4}

and

C O_{2}

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	C	H
mass per 100g	75	25
no of moles	$\frac{75}{12}$ $= 6.25$	$\frac{25}{1}$ =25
Divide by 6.25	1	4

A hydrocarbon contains 75% of carbon. Then its molecular formula will be :

The correct option is B CH4 CHmass per 100g 7525no of moles7512=6.25251=25Divide by 6.2514MF is CH4

The correct option is B $C H_{4}$
C H
mass per 100g 75 25
no of moles $\frac{75}{12}$
$= 6.25$ $\frac{25}{1}$
=25
Divide by 6.25 1 4
MF is $C H_{4}$