A hydrocarbon contains $80 % C$ of carbon and its vapour density is $30$ . The hydrocarbon is :

C H_{3}

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C_{2} H_{6}

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C_{4} H_{12}

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Solution

The correct option is C $C_{4} H_{12}$
Ratio between $C : H$ is given as = $80 : 20$ .
Molar ratio is $\frac{80}{12} : \frac{20}{1}$ = $1 : 3$ .
The formula of compound is $C_{2} H_{6}$ .

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A hydrocarbon contains 80%C of carbon and its vapour density is 30. The hydrocarbon is :

The correct option is C C4H12Ratio between C:H is given as = 80:20.Molar ratio is 8012:201 = 1:3. The formula of compound is C2H6.

A hydrocarbon contains $80 % C$ of carbon and its vapour density is $30$ . The hydrocarbon is :

The correct option is C $C_{4} H_{12}$
Ratio between $C : H$ is given as = $80 : 20$ .
Molar ratio is $\frac{80}{12} : \frac{20}{1}$ = $1 : 3$ .
The formula of compound is $C_{2} H_{6}$ .