A hydrocarbon having empirical formula as $C H_{2}$ has a density of 1.25g/L. The molecular formula of the hydrocarbon is

C₂H₂

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C₂H₄

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C₂H₆

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C₃H₈

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Solution

The correct option is B
C₂H₄

1.2g is present in 1 litre.

Amount present in 22.4L $= 22.4 \times 1.2 g = 28 g$

(As 1 moloe substance occupies 22.4L)

molecular mass=28g

emprical mass =14g ( $C H_{2} = 12 + 2 = 14)$

$n = \frac{28}{14} = 2$

molecular formula= $C H_{2} \times 2 = C_{2} H_{4}$

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A hydrocarbon having empirical formula as CH2 has a density of 1.25g/L. The molecular formula of the hydrocarbon is

The correct option is B C2H4 1.2g is present in 1 litre. Amount present in 22.4L =22.4×1.2g =28g (As 1 moloe substance occupies 22.4L) molecular mass=28g emprical mass =14g (CH2=12+2=14) n=2814=2 molecular formula=CH2×2=C2H4

A hydrocarbon having empirical formula as $C H_{2}$ has a density of 1.25g/L. The molecular formula of the hydrocarbon is

The correct option is B
C₂H₄

1.2g is present in 1 litre.

Amount present in 22.4L $= 22.4 \times 1.2 g = 28 g$

(As 1 moloe substance occupies 22.4L)

molecular mass=28g

emprical mass =14g ( $C H_{2} = 12 + 2 = 14)$

$n = \frac{28}{14} = 2$

molecular formula= $C H_{2} \times 2 = C_{2} H_{4}$