A hydrocarbon is composed of 75% carbon. The empirical formula of the compound is:

C H_{2}

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C H_{3}

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C H_{4}

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C_{2} H_{7}

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Solution

The correct option is B $C H_{4}$
Calculation of empirical formula :

Element % Weight At. Mass $= \frac{N o . o f m o l e s}{at. mass}$ Simplest molar ratio
$C$ $75$ $12$ $\frac{75}{12} = 6.25$ $1$
$H$ $25$ $1$ $\frac{25}{1} = 25$ $4$
Thus, the empirical formula of the compound is $C H_{4}$

Option C is correct.

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