A hydrocarbon on ozonolysis gives two moles of acetone. The type of hybridization that carbons undergoes in that hydrocarbon are

4 - sp³ and 2 - sp²

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2 - sp³ and 4 - sp²

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4 - sp³ and 4 - sp²

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2 - sp³ and 2 - sp²

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Solution

The correct option is A
4 - sp³ and 2 - sp²

$C H_{3} - C (C H_{3}) = C (C H_{3})_{2}$ gives acetone on ozonolysis

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C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

C (1) H_{2} = C (2) H - C (3) \equiv C H

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