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Oxidation of Alkenes

A hydrocarbon...

Question

A hydrocarbon X adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X reacts with $K M n O_{4}$ in presence of acid to give two moles of the same carboxylic acid. The structure of X is

C H_{2} = C H - C H_{2} C H_{2} C H_{3}

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C H_{3} C H_{2} C H_{2} - C H = C H C H_{3}

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C H_{3} C H_{2} C H = C H C H_{2} C H_{3}

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C H_{3} C H = C H C H_{2} C H_{2} C H_{3}

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Solution

The correct option is C $C H_{3} C H_{2} C H = C H C H_{2} C H_{3}$
Since it produces the same carboxylic acid, it should have a symmetrically centralised double bond(groups on either side of the double bond are the same). Using that concept, the answer is $C H_{3} C H_{2} C H = C H C H_{2} C H_{3}$

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