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Byju's Answer
Standard XII
Chemistry
Reaction with Metals
A hydrocarbon...
Question

A hydrocarbon (X) of the formula C6H12 does not react with bromine water but reacts with the bromine in presence of light, forming compound (Y). Y on treatment with alc. KOH gives compound (Z) which on ozonolysis gives (T) of the formula C6H10O2. T reduces Tollens's reagent which give compound (W) on acidification. W gives iodoform test and after acidification produces compound (U) which when heated with P2O5 forms a cyclic anhydride (V).

A
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B
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C
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D
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Solution

The correct options are
B
C
AS (X) does not react with bromine water hence it is not alkene. As it reacts with bromine in presence of light it is alkane.

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Q. A hydrocarbon (A) of the formula C6H12 (does not have a three membered ring) does not react with Br2/H2O but reacts with Br2/hv such that it can form 4 monobromo derivatives. The major product (B) obtained from photobromination, on treatment with alc. KOH gives compound (C) which on reductive ozonolysis gives (D) of the formula C6H10O2. Compound (D) reduces Tollens' reagent and gives compound (X). (X) gives iodoform test and produces compound (Y) after acidification. (Y) when heated with P2O5 forms a cyclic anhydride (Z).

List-I contains questions related to compounds of given Paragraph and List-II contains their answers.

List-IList-II(I)Which compound on oxidative ozonolysis gives (X)?(P)(Z)(II)Which compound on heating with dilute NaOH gives cyclohex-2-enone? (Q)(B)(III)Which compound is formed when cyclopentane-1, 2- dione is oxidized with CF3COOOH?(R)(C)(IV)Which compound will give methylenecyclopentane when heated with sodium tert-butoxide?(S)(A)(T)(Y)(U)(D)

Which of the following options has the correct combination considering List-I and List-II
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