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Question

A hydrogen atom and a Li++ ion are both in second excited state. If lH and lLi are their respective electronic angular momenta, and EH and ELi their respective energies, then
(IIT-JEE-2002)


A

lH>lLi and |EH|>|ELi|

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B

lH=lLi and |EH|<|ELi|

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C

lH=lLi and |EH|>|ELi|

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D

lH<lLi and |EH|<|ELi|

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Solution

The correct option is B

lH=lLi and |EH|<|ELi|


Since the angular momentum of an electron in the Bohr’s Atomic model is l=nh2π. It only depends on the principle quantum number. So,lH=lLi.

Also, Since energy is directly proportional to the square of the atomic number. The magnitude of energy of Lithium ion is more than the magnitude of energy of Hydrogen atom.


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