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Nature of Electromagnetic Radiation

A hydrogen at...

Question

A hydrogen atom (ionization energy $13.6 e V$ ) jumps from third excited state to first excited state. The energy of a photon emitted in the process is:

A

1.89 e V

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B

2.55 e V

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C

12.09 e V

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D

12.75 e V

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Solution

The correct option is B $2.55 e V$

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Similar questions

Q. The ionization energy of hydrogen is

13.6 e V

. The energy of the photon released when an electron jumps from the first excited state

(n = 2)

to the ground state of a hydrogen atom is:

Q. The ionization energy of hydrogen atom is

13.6 e V .

The energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is:

Q. A hydrogen-like atom (atomic number

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) is in a higher excited state of the quantum number

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10.20 e V

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Alternatively, the atom from the same excited state can make a transition to the second excites state by the successively emitting two photons of energy

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of the photons emitted in this process is:

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