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Question

A hydrogen atom is in ground state. In order to get six lines in its emission spectrum, wavelengths of incident radiation should be,

A
800 ˚A
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B
825 ˚A
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C
975 ˚A
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D
1025 ˚A
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Solution

The correct option is C 975 ˚A
The number of spectral lines emitted, during transition is, n(n1)2
6=n2(n1)
12=n2n
n2n12=0
n24n+3n12=0
n(n4)+3(n4)=0
(n+3)(n4)=0
n=3,4
Considering positive value, we have n=4
Now, 1λ=R(112142)
λ=1615R=975 ˚A

Hence, (C) is the correct answer.

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