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Question

A hydrogen electrode placed in a solution containing sodium acetate and acetic acid in the ratio of x:y and y:x has an electrode potential value E1 and E2 volts, respectively, at 25C. The pKa value of acetic acid is:

A
(E1+E1)2×0.059
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B
E1+E22×0.059
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C
E2E12×0.059
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D
(E1+E2)0.059
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Solution

The correct option is A (E1+E1)2×0.059

Pt|H2|Sodiumacetate+CH3COOH(x:y)

pH of acidic buffer = pKa+log(SaltAcid)

pH1=pKa+logxy

Similarly, pH2=pKa+logxy

E1=0.059pH1

E2=0.059pH2

(E1+E2)=0.059(pKa+logxy)

0.059(pKa+logyx)

pKa=(E1+E2)2 ×0.059


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