Question

A hydrogen gas electrode is made by dipping platinum wire in a solution of $HCl$ of $pH=10$ and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be:
(NEET-UG-2013)

• A. $0.118V$
• B. $0.59V$
• C. $0.059V$
• D. $1018V$

Answer 1

The correct option is B $0.59V$

Given, $pH=10$ $\left[H^{+}\right]={10}^{-10}M$ The pressure of hydrogen gas is one atm. The oxidation potential of electrode would be $E_{cell}=-\frac{0.059}{n}log\frac{\left[H^{+}\right]}{(P_{H_2}{)}^{1/2}}$ $E_{cell}=-\frac{0.059}{1}log\frac{{10}^{-10}}{(1{)}^{1/2}}$ $E_{cell}=0.59V$