Question

A hydrogen like system has ionisation energy $11808$ kJ/mol. Find the number of protons in the nucleus of the system.

Answer 1

$13.6\times z^2[\frac{1}{n^2}-\frac{1}{m^2}]$ $[n=1,m=\infty ]$
$13.6\frac{z^2}{1}=\frac{11808}{96.4}$
$z^2=\frac{11808}{96.4\times 13.6}=\frac{11808}{1311.04}$
$=9.00$
$z=3$