A hyperbola has its centre at the origin, passes through the point (4,2) and has transverse axis of length 4 unit along the x−axis. Then the eccentricity of the hyperbola is
A
√3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2√3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2√3 Given 2a=4 ⇒a=2
The hyperbola x2a2−y2b2=1
passes through (4,2)
So, 4222−22b2=1 ⇒b2=43 ∴e=√1+b2a2=2√3