The correct option is B (2√2,3√3)
(ae)2=4⇒b2=4−a2
Thus, equation of hyperbola is x2a2−y24−a2=1
Given, the hyperbola passes through P(√2,√3).
⇒2a2−34−a2=1
⇒a2=1,8 [Ignoring a2=8 as a2<(ae)2]
⇒a2=1
∴ Equation of hyperbola is x21−y23=1
Slope of tangent at P(√2,√3) is dydx∣∣(√2,√3)=√6
∴ Equation of tangent at P(√2,√3) is y−√3=√6(x−√2)
Hence, the tangent passes through (2√2,3√3).