A hyperbola passing through origin has 3x – 4y – 1=0 and 4x – 3y – 6 = 0 as its asymptotes. Then the equations of its transverse and conjugate axes are

x – y – 5 = 0 and x + y + 1 = 0

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x – y = 0 and x + y + 5 = 0

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x + y – 5 = 0 and x – y – 1 = 0

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x + y – 1 = 0 and x – y – 5 = 0

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Solution

The correct option is C
x + y – 5 = 0 and x – y – 1 = 0

Transverse and conjugate axes are the bisectors of the angle between asymptotes.

$\frac{3 x - 4 y - 1}{5} = \pm (\frac{4 x - 3 y - 6}{5}) e t c \dots$

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A hyperbola passing through origin has 3x – 4y – 1=0 and 4x – 3y – 6 = 0 as its asymptotes. Then the equations of its transverse and conjugate axes are

The correct option is C x + y – 5 = 0 and x – y – 1 = 0 Transverse and conjugate axes are the bisectors of the angle between asymptotes. 3x−4y−15=±(4x−3y−65) etc⋯

The correct option is C
x + y – 5 = 0 and x – y – 1 = 0

Transverse and conjugate axes are the bisectors of the angle between asymptotes.

$\frac{3 x - 4 y - 1}{5} = \pm (\frac{4 x - 3 y - 6}{5}) e t c \dots$