Question

A hyperbola passing through origin has 3x – 4y – 1=0 and 4x – 3y – 6 = 0 as its asymptotes. Then the equations of its transverse and conjugate axes are

• A. x – y – 5 = 0 and x + y + 1 = 0
• B. x – y = 0 and x + y + 5 = 0
• C. x + y – 5 = 0 and x – y – 1 = 0
• D. x + y – 1 = 0 and x – y – 5 = 0

Answer 1

The correct option is C

x + y – 5 = 0 and x – y – 1 = 0

Transverse and conjugate axes are the bisectors of the angle between asymptotes.

$\frac{3x-4y-1}{5}=\pm \left(\frac{4x-3y-6}{5}\right)etc\cdots \cdots$