A hyperbola with the assymptotes 3x + 4y = 2 and 4x - 3y = 2 is a rectangular hyperbola.

False

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True

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Solution

The correct option is B True

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Similar questions

\frac{(3 x - 4 y - 12)^{2}}{100} - \frac{(4 x + 3 y - 12)^{2}}{225} = 1

3 x + 4 y = 0

4 x + 3 y = 0

\frac{(3 x - 4 y - 12)^{2}}{225} - \frac{(4 x + 3 y - 12)^{2}}{100} = 1

\frac{(3 x - 4 y - 12)^{2}}{100} - \frac{(4 x + 3 y - 12)^{2}}{225} = 1

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