Question

A hypothetical engineering stress-strain curve shown in the figure has three straight lines PQ, QR, RS with coordinates P(0,0), Q (0.2, 100), R (0.6, 140) and S (0.8, 130). Q is the yield point, R is the UTS point and S the fracture point.


The toughness of the material (in MJ/ $m^3$) is

• A. 0.85

Answer 1

The correct option is A 0.85
Toughness is area of curve upto S on strain axis

$\{\frac{1}{2}\times \frac{0.2}{100}\times 100\}+\{\frac{100+140}{2}\times \frac{0.4}{100}\}+\left\{\frac{140+130}{2}\right\}\times \frac{0.2}{100}$

$=0.1+0.48+0.27=0.85MJ/m^3$