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Question

A hypothetical nuclear fission takes place as following:

23692X 14056Y + 9436Y + neutrons

How many neutrons will get emitted in the process?

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 2
23692X 14056Y + 9436Y + neutrons

Z in LHS = 92
Z in RHS = 56 + 36 = 92

A in LHS = 236
A in RHS = 234
A required in RHS = 236 - 234 = 2

We know a neutron is 10n which has a Z of 1. So, two neutrons are emitted in the process.

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