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Standard XII

Chemistry

Effective Equilibrium Constant

A hypothetica...

Question

A hypothetical reaction : $A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}$ occurs in a single step, the specific rate constant of forward reaction at TK is $2.0 \times 10^{- 3} m o l^{- 1} L s^{- 1}$ . When start is made with equimolar amounts of A and B, it is found that the concentration of A is twice that of C at equilibrium. The specific rate constant of the backward reaction is ?

$5.0 \times 10^{- 4} m o l^{- 1} L s^{- 1}$

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$8.0 \times 10^{- 3} m o l^{- 1} L s^{- 1}$

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$1.5 \times 10^{2} m o l^{- 1} L s^{- 1}$

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$N o n e o f t h e s e$

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Solution

The correct option is B
$8.0 \times 10^{- 3} m o l^{- 1} L s^{- 1}$

$\begin{matrix} A & + & B & ⇌ & C & + & D a & a & 0 & 0 a - x & a - x & x & x \end{matrix} G i v e n : a - x = 2 x, x = \frac{a}{3}; K_{C} = \frac{x \times x}{(a - x) (a - x)} = 0.25; K_{C} = \frac{K_{f}}{K_{b}}; K_{b} = \frac{K_{f}}{K_{c}} = \frac{2 \times 10^{- 3}}{0.25} = 8 \times 10^{- 3}$

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Similar questions

A hypothetical reaction : $A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}$ occurs in a single step, the specific rate constant of forward reaction at TK is $2.0 \times 10^{- 3} m o l^{- 1} L s^{- 1}$ . When start is made with equimolar amounts of A and B, it is found that the concentration of A is twice that of C at equilibrium. The specific rate constant of the backward reaction is ?

Q. The reaction

A (g) + B (g) ⇌ C (g) + D (g)

is elementry

2^{n d}

order reaction. When started with equimolar amounts of A and B, at equilibrium, it is found that the concentration of A is twice that of C. Specific rate for forward reaction is

2 \times 10^{- 3} m o l^{- 1} L s e c^{- 1}

. The specific rate constant for backward reaction is:

Q. The rate constant of a reaction is

k = 3.4 \times 10^{- 4} m o l^{- 1} L s^{- 1}

. What is the order of reaction?

1 m o l e

of a gas

^{'} A^{'}

is taken in a vessel of volume

1 L

. It dissociated according to the reaction

A (g) ⇌ B (g) + C (g)

27

. Forward and backward reaction rate constants for the reaction are

1.5 \times 10^{- 2}

and

3 \times 10^{- 2}

respectively. Find the concentration of

A

B

and

C

at equilibrium. Also find

K_{R}

and

K_{c}

with proper units.

Consider the reaction.

$A_{(g)} + B_{(g)} ⇌ C_{(g)} + D_{(g)}$ which occurs in one step. The specific rate constants are 0.25 and 5000 for the forward and reverse reaction, respectively. The equilibrium constant is

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The correct option is B 8.0×10−3mol−1Ls−1 A+B⇌C+Daa00a−xa−xxxGiven:a−x=2x,x=a3;KC=x×x(a−x)(a−x)=0.25;KC=KfKb;Kb=KfKc=2×10−30.25=8×10−3