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Question

A hypothetical reaction A2+B22AB follows the mechanism as given below: A2A+A(fast)A+B2AB+B(slow)A+BAB(fast)The order of the overall reaction is:


A

2

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B

1

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C

1.5

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D

0

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Solution

The correct option is C

1.5


The explanation for the correct option:

Option(C):

  • The order of reaction refers to the relationship between the rate of a chemical reaction and the concentration of the species taking part in it.
  • In order to obtain the reaction order, the rate expression (or the rate equation) of the reaction in question must be obtained.
  • Reaction order represents the number of species whose concentration directly affects the rate of reaction.

Step 1: Given data:

Since (A) is the intermediate reactive substance whose concentration is determined from the equilibrium step.

Let us consider the slow step of the reaction

A+B2AB+B (slow)

r=k[A][B2]…………….(1)

Step 2: Deriving rate law:

From the equilibrium step

A2A+A(fast)

keq=[A]2/[A2][A]=keq[A2]1/2

Step 3:Determination of rate

Substitute the value of [A] in equation (1)

r=k[keq[A2]1/2][B2]r=k.keq1/2.[A2]11/2.B2

Step 4: Calculating the order of the reaction:

Thus, the order of the reaction is

1/2+13/21.5

Hence the order of the overall reaction is 1.5, option (C) is the correct answer.


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