Question

A hypothetical screw gauge has a pitch of $0.2\text{mm}$ and $10$ divisions on circular scale. The least count of screw gauge is

Answer 1

For a screw gauge, Least count is given as

$\text{Least count}=\frac{\text{Pitch}}{\text{Number of divisions on circular scale}}$

$=\frac{0.2}{10}=0.02\text{mm}$