a + ib > c + id can be explained only when

b = 0, c = 0

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b = 0, d = 0

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a = 0, c = 0

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a = 0, d = 0

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Solution

The correct option is B
b = 0, d = 0

We cannot compare 2 complex numbers as they have imaginary parts.

a + ib > c + id can be defined if and only if imaginary parts are zero.

i.e., so, b =0, d = 0

Suggest Corrections

Similar questions

a + ib > c + id can be explained only when

a + i b > c + i d

a + ib > c + id can be explained only when

∣ ∣ ∣ \begin{matrix} a + i b & c + i d - c + i d & a - i b \end{matrix} ∣ ∣ ∣ \times ∣ ∣ ∣ \begin{matrix} a - i β & γ - i δ - γ - i δ & a + i β \end{matrix} ∣ ∣ ∣

i = \sqrt{- 1}

∣ ∣ ∣ \begin{matrix} A - i B & C - i D - C - i D & A + i B \end{matrix} ∣ ∣ ∣

\frac{a + i b}{c + i d} = p + i q

\frac{a - i b}{c - i d} = p - i q

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