wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

(a) In what way is different from each slit related to the interference pattern in a double slit experiment
(b) Two wavelength of sodium light 590 nm and 596 nm are used in turn to study the diffraction taking place at a single slit of aperture 2×104m, The distance between the slit and the screen is 1.5m, Calculate the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases.

Open in App
Solution

(a) If the width of each slit is comparable to the wavelength of light used, the interference pattern thus obtained in the double-slit experiment is modified by diffraction from each of the two slit.
(b) Give that Wavelength of the light beam, λ1=590nm=5.9×107m
Wavelength of the light beam, λ2=596nm=5.96×107m
Distance of the slit from the screen =D+1.5m
Distance between the two slits, a=2×104m
For the first secondary maxima, sinθ=3λ12a=xiD
X1=3λ1D2aandX2=3λ2D2a
X1=3×590×109×152×2×104,X2=3×596×109×1.52×2×104
X1=663.75×105,X2=670.50×105
Spacing between the position of first secondary maxima of two sodium lines
X2X1=6.75×105m=0.0675mm

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Superposition Recap
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon