A∞M and A∞eq. are molar and equivalent conductivities at infinite dilution; λ is ionic conductivity at infinite dilution, then for potash alum:
A
A∞M (potash alum)=2×λ∞K++2×λ∞Al3++4×λ∞SO2−4
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B
A∞eq (potash alum)=18×A∞M (potash alum)
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C
A∞M (potash alum)=14×λ∞K++14×λ∞Al3++12×λ∞SO2−4
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D
A∞M (potash alum)=λ∞K++λ∞Al3++λ∞SO2−4
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Solution
The correct options are AA∞M (potash alum)=2×λ∞K++2×λ∞Al3++4×λ∞SO2−4 CA∞eq (potash alum)=18×A∞M (potash alum) A∞M and A∞eq. are molar and equivalent conductivities at infinite dilution; λ is ionic conductivity at infinite dilution, then for potash alum
(A) A∞M (potash alum)=2×λ∞K++2×λ∞Al3++4×λ∞SO2−4
The molar conductivity is equal to the sum of the ionic conductivities.
(B) A∞eq (potash alum)=18×A∞M (potash alum) [Note : charge will be 8]
The equivalent conductivity is one eight of the molar conductivity.