A is $20$ years older than B. $5$ years ago, A was $3$ times as old as B. Find their present ages.

35

years and

15

years

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5

years and

25

years

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18

years and

42

years

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21

years and

44

years

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Solution

The correct option is A $35$ years and $15$ years
Let the numbers be $x$ and $y$
$x = 20 + y$
$x - 5 = 3 (y - 5)$
Substituting value of $x$ in the 2nd equation:
$[20 + y] - 5 = 3 (y - 5)$
Therefore, $x = 35, y = 15$

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A is 20 years older than B. 5 years ago, A was 3 times as old as B. Find their present ages.

The correct option is A 35 years and 15 yearsLet the numbers be x and yx=20+yx−5=3(y−5)Substituting value of x in the 2nd equation:[20+y]−5=3(y−5)Therefore, x=35,y=15

A is $20$ years older than B. $5$ years ago, A was $3$ times as old as B. Find their present ages.

The correct option is A $35$ years and $15$ years
Let the numbers be $x$ and $y$
$x = 20 + y$
$x - 5 = 3 (y - 5)$
Substituting value of $x$ in the 2nd equation:
$[20 + y] - 5 = 3 (y - 5)$
Therefore, $x = 35, y = 15$