$A$ is $3$ years older to $B$ and $3$ years younger to $C$ , while $B$ and $D$ are twins. How many years older is $C$ to $D$ ?

2

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Solution

The correct option is A $6$
Since $B$ and $D$ are twins, so $B = D$ .
Now, $A = B + 3$ and $A = C - 3$ .
Thus, $B + 3 = C - 3 \Leftrightarrow D + 3 = C - 3 \Leftrightarrow C - D = 6$ .

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A is 3 years older to B and 3 years younger to C, while B and D are twins. How many years older is C to D?

The correct option is A 6Since B and D are twins, so B=D.Now, A=B+3 and A=C−3.Thus, B+3=C−3⇔D+3=C−3⇔C−D=6.

$A$ is $3$ years older to $B$ and $3$ years younger to $C$ , while $B$ and $D$ are twins. How many years older is $C$ to $D$ ?

The correct option is A $6$
Since $B$ and $D$ are twins, so $B = D$ .
Now, $A = B + 3$ and $A = C - 3$ .
Thus, $B + 3 = C - 3 \Leftrightarrow D + 3 = C - 3 \Leftrightarrow C - D = 6$ .