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Preparations and Reactions of Sodium Oxide

A is a binary...

Question

(A) is a binary compound of a univalent metal 1.422 g of (A) reacts completely with 0.321 g of sulphur in an evacuated and sealed tube to give 1.743 g of a white crystalline solid (B), that forms a hydrated double salt (C) with ${A l}_{2} ({S O}_{4})_{3}$ . Here (A), (B) and (C) are identified as (A): $K O_{2}$ , (B): $K_{2} S O_{4}$ and (C): $K_{2} S O_{4} . A l_{2} (S O_{4})_{2} a l u m . 24 H_{2} O$ .

If the given statement is true enter 1 else 0.

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Solution

A is binary salt of univalent metal A converts S to sulphate.Hence A contains oxygen. Since, A is a binary salt thus A can be
$M O_{2}$ (superoxide) with $O_{2}^{-}$ anion.
1 mole of S corresponds to 1 mole of sulphate.
Let M be the molecular mass of metal in A.
$M O_{2} (M + 32) + S 32 ⟶ M_{2} S O_{4} (2 M + 96)$
$\frac{2 M + 96}{32} = \frac{1.743}{0.321}$
Hence, $M = 38.87 = 39$
Thus, binary compound
A is $K O_{2}$ , B is $K_{2} S O_{4}$ , C is $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} (a l u m) .24 H_{2} O$

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