The correct option is C P(E)=nCr3r4n
Let A={a1,a2,a3,...an}
For each ai∈A(1≤i≤n)
we have following four cases:
i) ai∈P and ai∈Q
ii) ai∉P and ai∈Q
iii) ai∈P and ai∉Q
iv) ai∉P and ai∉Q
Thus the total numbers of ways of choosing P and Q is 4n
and choosing exactly r elements in (P∪Q) is nCr3r
Therefore required probability =nCr3r4n