A is an object with image size 4 cm and O’ A’ is the image of the object. Find out the image height and nature of the image formed.

3 cm, erect

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2cm, inverted

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4 cm, inverted

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3cm, inverted

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Solution

The correct option is B
2cm, inverted

Magnification = $\frac{v}{u}$ = $\frac{h^{/}}{h}$

$\Rightarrow$ $\frac{+ 15}{- 30}$ = $\frac{h^{/}}{(4)}$

$h^{/}$ = $\frac{- 4}{2}$ = - 2 cm

Image height is 2 cm and inverted.

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