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Question
A is elder to B by 2 years. A’s father F is twice as old as A and B is twice as old as his sister S. If the ages of the father and sister differ by 40 years, find the age of A.
A is elder to B by 2 years. A’s father F is twice as old as A and B is twice as old as his sister S. If the ages of the father and sister differ by 40 years, find the age of A.
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Solution
Let age of A be A years,
age of B be B years
age of F be F years
age of S be S years
ATQ, A = B + 2 ........(1)
F = 2A ......(2)
B = 2S ........(3)
F - S = 40 ........(4)
Substituting equations (2) & (3) in (4),
2A - B/2 = 40
=> 4A - B = 80 .........(5)
Solving eqn (1) & (5), we get
3A = 78
=> A = 26
age of B be B years
age of F be F years
age of S be S years
ATQ, A = B + 2 ........(1)
F = 2A ......(2)
B = 2S ........(3)
F - S = 40 ........(4)
Substituting equations (2) & (3) in (4),
2A - B/2 = 40
=> 4A - B = 80 .........(5)
Solving eqn (1) & (5), we get
3A = 78
=> A = 26
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