A is faster than B A and B each walk 24 km The sum of their speeds is 7 km/hr and sum of times taken by them is 14 hours Then A's speed is equal to

3 km/hr

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4 km/hr

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5 km/hr

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7 km/hr

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Solution

The correct option is B 4 km/hr
Let A's speed = x km/hr Then B's speed = (7 - x) km/hr So, $\frac{24}{x} + \frac{24}{(7 - x)} = 14$
$\Rightarrow 24 (7 - x) + 24 x = 14 x (7 - x) \Rightarrow 168 = 98 x - 14 x^{2} \Rightarrow 14 x^{2} - 98 x + 168 = 0$
$\Rightarrow x^{2} - 7 x + 12 = 0 \Rightarrow (x - 3) (x - 4) = 0 \Rightarrow x = 3 o r 4$
Since A is faster than B, A's speed = 4 km/hr and B's speed = 3 km/hr

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A is faster than B A and B each walk 24 km The sum of their speeds is 7 km/hr and sum of times taken by them is 14 hours Then A's speed is equal to

The correct option is B 4 km/hrLet A's speed = x km/hr Then B's speed = (7 - x) km/hr So, 24x+24(7−x)=14⇒24(7−x)+24x=14x(7−x)⇒168=98x−14x2⇒14x2−98x+168=0⇒x2−7x+12=0⇒(x−3)(x−4)=0⇒x=3or4Since A is faster than B, A's speed = 4 km/hr and B's speed = 3 km/hr