A is older than B. Taking present ages of A and B as x years and y years respectively, find in terms of x and y :
The age of B when A was of y years.
A
(2y−3x) years
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B
(y−2x) years
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C
(y−x) years
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D
(2y−x) years
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Solution
The correct option is D(2y−x) years Since, A is older than B, when x was y years old => he was (x−y) years younger. This means, B was also (x−y) years younger, or =y−(x−y)=2y−x years old.