Question

A is older than B. Taking present ages of A and B as $x$ years and $y$ years respectively, find in terms of $x$ and $y$:
(i) the difference between the ages of A and B.
(ii) the age of B when A was of $y$ years.
If the age of B, obtained, in step (ii), is half the present age of A and B is 42 years; find the present ages of A and B.

Answer 1

(i) Difference of their ages $=x-y$
(ii) Since, A is older than B, when $x$ was $y$ years old =>
he was $(x-y)$ years younger. This means, B was also $(x-y)$ years
younger, or $=y-(x-y)=2y-x$ years old.
(iii) Not solvable. Information is not clear.