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Question

A is the bottom most point of a particle describing a vertical circle of radius R. At point B, the acceleration of the particle is g11. Find the velocity of the particle at top point C :

A
[gR(102)]12
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B
[gR]12
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C
[gR(112)]12
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D
None of these
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Solution

The correct option is A [gR(102)]12
Net acceleration at point B is given by
a=(a2C+a2T)12=g11
But aT=g
a2C=11g2g2=10g2
ac=g10=V2BR
V2B=gR10
Using kinematics equation,
V2C=V2B2gR=gR(102)
VC=gR(102)

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