Question

$A$ is twice as old as $B$, ten years ago he was four times as old. What are their present ages?

Answer 1

let the age of A be x yeras and the age of B be y years old

then according to the question

$x=2y$ -equation1

$x-10=4(y-10)$ -equation2

from equation1 and equation2

$2y-10=4y-40$

$2y=30$

$y=15years$

putting value of y in equation 1

$x=2y$$=2\times 15=30$ years

Age of A$=30$years

Age of B$=15$ years