A jar of syrup with 13cm of height is kept on the floor. Find the pressure of water at the bottom of the jar.
(Ignore the atmospheric pressure and use the acceleration due to gravity,
$g = 10 m / s^{2}$
and, the density of water $1000 k g / m^{3}$ )

890 Pa

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1100 Pa

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1300 Pa

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1330 Pa

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Solution

The correct option is C
1300 Pa

The pressure at the depth of 13 cm:
$P = ρ \times g \times h$
$P = 1000 \times 10 \times 0.13 = 1300 P a s c a l$

Suggest Corrections

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )

Water and oil are taken in two separate beakers, the density of water is $1000 k g / m^{3}$ and the density of oil is $1500 k g / m^{3}$ . At what depth, the pressure in oil beaker will be the same as the pressure at $150 c m$ in the water beaker? (Acceleration due to gravity = $10 m / s^{2}$ )

Q. If pressure at half depth of a lake is equal to

\frac{2}{3} r d

pressure at the bottom of the lake, then what is the depth of the lake?
(Take atmospheric pressure as

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, density of water as

1000 {kg/m}^{3}

and

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)

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A cylindrical vessel of base radius 1 m and height 2m is completely filled with liquid of density 2 x 10 $^{3}$ kg/m $^{3}$ . Thrust at the bottom =3 x 10 $^{3}$ , Ignore the atmospheric pressure and find the pressure exerted by the water at the bottom of the cylinder.

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A jar of syrup with 13cm of height is kept on the floor. Find the pressure of water at the bottom of the jar. (Ignore the atmospheric pressure and use the acceleration due to gravity, g=10m/s2 and, the density of water 1000kg/m3)

The correct option is C 1300 Pa The pressure at the depth of 13 cm: P=ρ×g×h P=1000×10×0.13=1300 Pascal

The maximum value of water pressure in the box in which water is filled upto a height of 4 m is equal to (atmospheric pressure =105 N/m2, density of water =1000 kg/m3, g=10 m/s2)

A jar of syrup with 13cm of height is kept on the floor. Find the pressure of water at the bottom of the jar.
(Ignore the atmospheric pressure and use the acceleration due to gravity,
$g = 10 m / s^{2}$
and, the density of water $1000 k g / m^{3}$ )

The correct option is C
1300 Pa

The pressure at the depth of 13 cm:
$P = ρ \times g \times h$
$P = 1000 \times 10 \times 0.13 = 1300 P a s c a l$

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )