A jet of water with area of cross-section 3cm2 strikes a wall at an angle θ=60o to the normal and be rebounds elastically from the wall with the same speed. If the speed of water in the jet is 12 m/s, then the force acting on the wall is
A
4.31N
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B
4.32×10−2N
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C
4.32×10−3N
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D
43.2N
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Solution
The correct option is D43.2N A=3cm2=3×10−4m2, θ=60o,u=12m/s F = Rate of change of momentum =2mucosθ=2×A×u×ρ×ucosθ [∴m=Volume×density=Auxρ] =2×3×10−4×12×12×103×cos60o =2×3×10−4×103×144×12 =432×10−1N=43.2N