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Question

A jet plane is at a vertical height of h. The angles of depression of two tanks on the horizontal ground are found to have measures α and β,α>β. Prove that the distance between the tanks is h(tanαtanβ)tanαtanβ assuming both the tanks are on the same side of the jet plane.

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Solution

Given that, a jet plane is at a vertical height of h. And the angles of depression of two tanks on the horizontal ground are found to have measures α and β such that α>β.
Based on the given information, we can draw the figure given above.
Let A be the position of the jet plane and C and D be the two tanks on the same side of the jet plane
Hence, AB=h
BC= distance between base and 1st tank =y
CD= distance between two tanks =x

Now, in ABC
tanα=ABBC
tanα=hy
y=htanα...(1)
In ABD
tanβ=ABBD
tanβ=hx+y
x+y=htanβ....(2)
From (1) and (2)
x+htanα=htanβ
x=htanβhtanα

x=h(tanαtanβ)tanαtanβ

Hence, the distance between the two tanks is h(tanαtanβ)tanαtanβ[Hence proved]

664399_625395_ans_86c4e9743afa4703bb7a07b5906f1a6f.png

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