A jeweller claims that he makes ornaments of pure gold that has a relative density of $19.3$ . He sells a bangle weighing $25.25 g$ to a person. The clever customer weighs the bangle when immersed in water and finds that it weighs $23.075 g$ in water. With the help of suitable calculations, find whether the ornament is made of pure gold or not.

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Solution

Step 1: Given data,
Weight of the bangle in air = $25.25 g$
Weight of the bangle in water = $23.075 g$
Relative density of pure gold bangle = $19.3$
Step 2: Finding the relative density of the gold bangle,
$R e l a t i v e d e n s i t y = \frac{w e i g h t o f t h e b a n g l e i n a i r}{w e i g h t o f t h e b a n g l e i n a i r - w e i g h t o f t h e b a n g l e i n w a t e r} = \frac{25.25 g}{25.25 g - 23.075 g} = 11.6$
Hence, the bangle is unpure as its relative density ( $11.6$ ) is not meeting up to the standards ( $19.3$ ).

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Q. A jeweller claims that he sells ornaments made of pure gold that has the relative density of 19.3. He sold a bangle weighing 25.25 gf to a person. The clever customer weighs that bangle when immersed in pure water and finds that it weighs 23.075 gf in water. Is the ornament made by pure gold?

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11.6

A jeweller sold a set of bangles weighing 25.25 g. When the weight of bangles was measured in water ,the purchaser found it to be 23.075 g .The relative density of pure gold is 19.3.

Using the data given ,find out if the bangles were made from pure gold or not.

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