Question

A jogger jogs along one length and breadth of a rectangular park. Its dimensions 150 ×120, find the distance and displacement?

Answer 1

Given dimensions = 150m×120m.
It means length =150m and breadth = 120m.
Distance travelled by the jogger = One length plus one breadth of the rectangular park
Distance travelled by the jogger = l + b = 150m + 120m = 270m.
As he starts from a point and reaches at a diagonally opposite point after travelling along one length and breadth. So, his displacement is equal to the diagonal of the rectangular field.

$\therefore Displacement=\sqrt{l^2+b^2}=\sqrt{{\left(150\right)}^2+{\left(120\right)}^2}$

$\Rightarrow Displacement=192.1m$.