Question

A joker's cap is n the form of a right circular cone of base radius 7 cm and height 24cm . Find the area of the sheet required to make 10 such caps.

Answer 1

Radius = 7cm
height = 24 cm

$l=\sqrt{2}+h^2$
$l={\sqrt{7}}^2+{24}^2$
$l=\sqrt{4}9+576$
$l=\sqrt{6}25$
l = 25

Curved surface area of one conical cap =
$\pi$ rl= (22/7) x (7) x25
= $550c{m}^2$


Curved surface area of 10 conical caps = $10x550c{m}^2$= $5500c{m}^2$

∴ the area of sheet required to make 10 conical caps is $5500c{m}^2$