A journey by car takes $48 m i n u t e s$ of $65 k m p h$ . How fast must the car go to finish the journey in $40 m i n t e s$ ?

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Solution

Time tajen by car to complete journey = 48 min
speed of car = 65 km/h
we know
speed= $\frac{D i s t a n c e}{t i m e}$
$65 = \frac{D}{(\frac{48}{60})}$
$D = 65 \times \frac{48}{60} = 52 k m$
$∴$ speed of car to cover this distance in 40 min
$s p e e d = \frac{52}{(\frac{40}{60})} = \frac{52}{40} \times 63 = 26 \times 3$
speed = 78 km/h

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A journey by car takes 48 minutes of 65 kmph. How fast must the car go to finish the journey in 40 mintes?

Time tajen by car to complete journey = 48 minspeed of car = 65 km/hwe knowspeed= Distancetime65=D(4860)D=65×4860=52km∴ speed of car to cover this distance in 40 minspeed=52(4060)=5240×63=26×3speed = 78 km/h

A journey by car takes $48 m i n u t e s$ of $65 k m p h$ . How fast must the car go to finish the journey in $40 m i n t e s$ ?