Question

Question 1 (a)
Judge the equivalent resistance when the following are connected in parallel−(a) $1\Omega$ and ${10}^6\Omega$.

Answer 1

(a) When $1\Omega$ and ${10}^6\Omega$ are connected in parallel:
Let R be the equivalent resistance.
$\therefore \frac{1}{R}=\frac{1}{1}+\frac{1}{{10}^6}$
$R=\frac{{10}^6}{1+{10}^6}\approx \frac{{10}^6}{{10}^6}=1\Omega$
Therefore, equivalent resistance is $1\Omega$.