A jug contains $2 L$ of milk. Calculate the volume of the milk in $m^{3}$ .

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Solution

$∵$ We know that

$1 m^{3} = 1000 L$ ${1 m = 10 d m o r 1 d m = \frac{1}{10} m = 10^{- 1} m; 1 m^{3} = 1000 d m^{3}}$

or $1 d m^{3} = 1 L$

or $1 c m^{3} = 10^{- 6} \times 1000 L$ ${1 m = 100 c m; 1 m^{3} = 10^{6} c m^{3}; 1 c m^{3} = 10^{- 6} m^{3}}$

or $1 c m^{3} = 10^{- 3} L = 1 m l$
Hence, $1 L = 1 d m^{3}$ ${1 L = 1000 m l}$

Then $2 L = 2 d m^{3} = 2 \times 10^{- 3} m^{3}$

Hence, $2 L m i l k = 2 \times 10^{- 3} m^{3}$

$Final Answer : 2 L = 2 \times 10^{- 3} m^{3}$

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